Saturday, April 6, 2013

Penny Jars and Cube Towers in Math

Our Math Workshop emphasis in recent weeks has been centered around analyzing relationships between two quantities in situations of constant change. These situations have started out very concretely, through using actual pennies and linking cubes, and then representing these situations more abstractly with arithmetic expressions.
In the above "penny jar" situation, there is a starting number of 5 pennies in the "jar". Then, 6 pennies are added each "round". The total number of pennies shown is (5 x 6) + 5, or 35 pennies. Students have been challenged to extend patterns such as this one, in order to determine the total number of pennies for any round. If asked to identify the number of pennies in the 20th round, for example, students would determine that there are 20 groups of 6 pennies (20 x 6), and then 5 more (+5) when including the "starting" pennies in the jar: 20 x 6 + 5 = 125. There would be 125 pennies in the jar after 20 rounds of adding 6 pennies each round. The most general arithmetic expression to represent "any" round might be n x 6 + 5, or 6n + 5.
These Investigations (from our Scott Foresman curriculum tool) have provided tables, such as the example shown above, in helping students make sense of (and represent) these situations algebraically.

In the above "double tower" situation, there are two skylights. As new "floors" are added to the double tower, the number of skylights never changes. Students have learned to represent this as "+2". Each time a floor is added, however, the double tower gains 6 new windows. The example above has 2 floors. This would be represented as 6 + 6 + 2, or 2 x 6 + 2. There are a total of 14 windows on this tower. Again, students have learned through active exploration (by actually constructing various towers with linking cube manipulatives as they fill in provided charts) how to represent this situation with a general arithmetic expression: n x 6 + 2 (6n + 2). How many windows would be on the 100th floor of this tower? To solve, students would simply calculate 100 x 6 + 2. A 100 floor double tower would have 602 windows.

Consider the two towers shown below: The Square Tower and Corner Tower.
How many windows (including skylights) would each of these towers have if they were 100 floors tall? Leave a comment with your answers. Be sure to share your thinking on how you arrive at your totals!!

Happy mathematizing!

6 comments:

  1. The square tower will have 804 if it had 100th floors because (8x100)+4=804. The corner tower would have 803 on the 100th floor becase (8x100)+3=803.Bobbi

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  2. The square tower would have 804 windows on the 100th floor and the corner tower would have 803 windows on the 100th floor

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  3. Hi, my daughter is a student at Jax Beach Elem., and she brought this homework home tonight, but just the single page from her book, with no instructions. I'm trying to help her with it, and I thought that a square tower would be just one block per floor, but the picture here shows four blocks per floor. I would like to confirm that because I'm obviously a little confused trying to help her. Thanks!

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  4. The square tower (as pictured in this post) has 8 windows on each floor and then one set of 4 skylights on the roof. The single tower (which is the first tower we study) has a simple arrangement of one cube stacked on top of the other- this tower has four windows and one skylight.

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  5. Thank you! My daughter had told me it was only one block per floor, but after I saw the picture here, I thought maybe she misunderstood her teacher. I believe she was correct, though. Thank you again!

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  6. The square tower would have 804 windows because (8 times 100=800 + 4 =804 windows on the 100th floor
    The corner tower would have 803 windows because (8 times 100= 800 + 3 =803 windows on the 100th floor
    Jordan S

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